geometric series test
-1 < r < 1 = convergent
divergent otherwise
alternating series test
lim n-> ∞ (1+k/n)^n/k = ?
e
ln(0) = ?
-∞
test for divergence
if Σan does not equal 0 then Σan is divergent (don’t know if it’s convergent or not)
p-series test
Σ1/n^p
p > 1 -> convergent
p < or equal to 1 -> divergent
if Σ|an| is convergent…
the original series is absolutely convergent
ratio test
lim n -> ∞ |an+1/an| = L
L < 1 -> Σan is A.C.
L > 1 -> Σan is divergent
L = 1 use other tests
root test
lim n -> ∞ n√|an| = L
L < 1 -> Σan is A.C.
L > 1 -> Σan is divergent
L = 1 use other tests
limit comparison test
an/bn cannot be 0 or ∞
if so, either are divergent or convergent
t/f: n! > 2^n
true