Inequalities and Abs value Flashcards
(14 cards)
Easiest way to visualize either of these is with __
a number line. Open circle means exclude and start after that number
You will always get ___ answers except with ___
2 answers both positive and negative
… except with ZERO which is categorized as neither
When fractions have the same denominators or share an LCM
multiply by that number to get whole values on both sides of the IQ sign
When zero is present on one side…
it is testing the positive/negative characteristics of the other side. If they share the same sign they’ll be greater than Zero
Better to avoid dividing and multiplying with…
a variable since the signage is unknown, you’ll never safely know whether to flip for negativity or not
Compound IQs are ideal because…
even if there is a divergent branch it makes the overall relationship of the values more digestible.
Line them up after simplifying and adopt the MOST limiting range
How do you manipulate compound IQ’s?
Follow the golden rule, identical to equations!
When can you add 2 IQ’s together?
ONLY when they share the same signage such as both pointing like “>”
Can I multiply 2 IQ’s?
ONLY if all possible values are positive or zero. If you’re given that condition go for it
What can I NOT do to 2 IQ’s
subtract or divide them
When dealing with a MINIMIZE problem what pair of numbers are you typically looking for when testing cases?
The largest negative and largest positive pair that follows the boundaries
When dealing with a MAXIMIZE problem what pair of numbers are you typically looking for when testing cases?
The highest pair of either both negative numbers or both positive numbers - they must share the same sign
Square root IQ’s are no joke! When taking a root you are essentially…
Solve X^2 >= 9
doing division, the signage of the target is unknown. Meaning you could have 2 possible answers and you are flipping the signage
X >= 3 and X <= -3
When looking at answer choices…
consider them as graphs or number lines. Turn the most restrictive range into a graph
