inorganic chemistry practice errors Flashcards

1
Q

explain in terms of equilibrium, why acidic conditions should not be used with cells containing CN- ions

A

H+ reacts with CN- to form HCN
so equilibrium shifts right and CN- is removed

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2
Q

suggest three advantages of using ethanol rather than hydrogen in a fuel cell for vehicles

A

ethanol is less flammable than hydrogen
ethanol is less volatile than hydrogen
ethanol is easier to store

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3
Q

define the term standard electrode potential

A

the electrode potential of a half cell compared to the standard hydrogen hal cell under standard conditions, i.e, 298K, 100KPa, and 1 moldm^-3

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4
Q

state two ways that hydrogen can be stored as fuels for vehicles

A

it can be stored on a solid material
it can be stored within a solid material

it can be stored in liquid form AND under pressure

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5
Q

state and explain the trend in atomic radius from Li to F (Li and F are in the same period)

A

atomic radius decreases because charge increases, due to the number of protons in the nucleus increasing

shielding stays the same

so there is a greater nuclear attraction between the outer shell electrons and the nucleus

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6
Q

the equation between chlorine and sodium hydroxide to form bleach and the conditions required for this reaction to take place

A

2NaOH + Cl2 –> NaCl + NaClO +H2O

room temperature and dilute NaOH

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7
Q

predict the structure and bonding of Barium Nitride

A

Giant ionic lattice

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8
Q

describe the trend of first ionization energy across a period

A

across a period, the atomic radius decreases
inner shielding stays the same
so nuclear attraction increases, and more energy is required to remove an electron from the atoms in the period

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9
Q

induced dipole-dipole forces act between which particles

A

molecules

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10
Q

describe the general trend of atomic radius across period 3

A

atomic radius decreases across period 3

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11
Q

why does magnesium have greater SECOND ionisation energy than strontium

A

Mg+ has a smaller ionic radius than Sr+

Mg+ experiences less shielding

so there is a greater nuclear attraction between the nucleus and outer electrons of Mg+ than Sr+

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12
Q

why is the boiling point of PH3 lower than that of NH3 (both are in the same group)

A

NH3 has hydrogen bonding while PH3 does not

Hydrogen bond stronger than induced-dipole dipole forces in PH3, so more energy required to overcome the forces in NH3

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13
Q

why is the boiling point of PH3 lower than the boiling point of AsH3 (As and P are all in the same group)

A

more electrons in AsH3 than PH3

so stronger induced dipole-dipole forces. therefore more energy is required to overcome the induced dipole-dipole interactions in AsH3

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14
Q

entropy

A

a measure of the dispersal of energy and disorder within the chemicals making up a system

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15
Q

formula for entropy

A

entropy of products- entropy of reactants

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16
Q

transition metals with only one electron in their 4s subshell

A

copper and chromium

17
Q

explain how ligand substitution allows hemoglobin to transport oxygen in the blood

A

oxygen binds to the iron ion in hemoglobin

when oxygen is required, the bond breaks to release it

18
Q

formula for calculating bond enthalpies

A

The formula for calculating bond enthalpies is:

ΔH = Σ (bond enthalpies broken) - Σ (bond enthalpies formed)

where ΔH is the enthalpy change of the reaction, and Σ (bond enthalpies broken) and Σ (bond enthalpies formed) are the sums of the bond enthalpies of the bonds broken and formed, respectively.

19
Q

the standard state of iodine

A

The standard state of iodine is a solid at 25°C and a pressure of 1 atm. The standard state of an element is the physical state of the element at 25°C and a pressure of 1 atm. For iodine, the solid form is the most stable at room temperature and atmospheric pressure, and is therefore considered to be the standard state.

20
Q

what is the unit of k if ln2/ t1/2 is used to calculate the value of k

A

s^-1

21
Q

why do industries try to avoid increasing temperature to very high levels, in order to increase the yield of their products?

why do industries try to avoid decreasing pressure to very low levels, in order to increase the yield of their products

A

because high temperatures use large amounts of energy

low pressure gives a low rate of reaction, so the yield will be higher, but it will take much longer to produce the products

22
Q

why do industries avoid using high pressures to maximize the yield of their products

A

high-pressure systems can be expensive to build and maintain, so industries must balance the benefits of higher yield against the higher costs of production

23
Q

standard conditions required to measure the standard cell potential

A

298 K temperature
100Kpa pressure
1 mol per dm cubed of solution

24
Q

what colour is the [Cu(H2O)6]2+

A

pale blue solution

25
Q

when [Cu(H2O)6]2+ reacts with HCl, what does it form
what colour is this new solution

A

[Cu(Cl)4]2-

yellow solution

26
Q

[Cu(H2O)6]2+ reacts with KI to form

what are the colors of the individual products

A

CuI and I2

white solid for CuI

brown solution for I2

27
Q

[Cu(H2O)6]2+ reacted with NH3 forms

[Cu(H2O)6]2+ reacted with excess NH3 forms

A

[Cu(NH3)6]2+

[Cu(NH3)4 (H2O)2]2+

28
Q

an aqueous solution of ethanoic acid contains both hydrogen and hydroxide ions
how can an aqueous solution of acid contain hydroxide ions

A

water dissociates to form H+ and OH-

29
Q

for a buffer solution to form, what needs to be present in the buffer

A

an acid and it’s conjugate base

30
Q

bond enthalpy breaking of one mole of bonds in gaseous molecules

A
31
Q

Enthalpy change of solution

A

Enthalpy change required for 1 mole of ionic compound to fully dissolve in water

32
Q

Enthalpy change of solution

A

Enthalpy change required for 1 mole of ionic compound to fully dissolve in water

33
Q

Formula for enthalpy change of solution

A

Sum of hydration enthalpies - lattice enthalpy

34
Q

Average bond enthalpies

A

Average amount of energy required to break one mole of bonds in GASEOUS molecules

35
Q

Is activation energy ever negative

A

No

36
Q

Use of cis Platin In medicine

A

It is used in the treatment of cancer , although it has unpleasant side effects

37
Q

colour of these transition metal ions
V3+
V2+

A

green
violet