maths Flashcards

1
Q

cosh2a =

A

2cosh(^2)a -1

1 + 2sinh(^2)a

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2
Q

tanha 2a =

A

2tanha / 1 + tanh(^2)a

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3
Q

what does 1 equal in hyperbolic functions

A

cosh(^2)a - sinh(^2)a =1

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4
Q

sech(^2)a=

A

1 - tanh(^2)a

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5
Q

-cosech(^2)a =

A

1- coth(^2)a

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6
Q

sinh(x+y) +

A

sinhxcoshx + sinhycoshx

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7
Q

cosh(x+y) =

A

coshxcoshy + sinhxsinhy

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8
Q

what does 1 equal in normal trig

A

cos(^2)a +sin(^2)a = 1

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9
Q

sec(^2)a =

A

1 +tan(^2)a

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10
Q

cosec(^2)a =

A

1 +cot(^2)a

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11
Q

sin2a =

A

2sinacosa

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12
Q

cos2a=

A

cos(^2)a - sinh(^2)a

2cos(^2)a - 1

1 - 2sin(^2)a

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13
Q

tan2a

A

= 2tana / 1-tan(^2)a

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14
Q

compex numbers

2cos(nx) =

A

z(^n) + 1/z(^n)

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15
Q

complex numbers

2isin(nx)

A

z (^n) - 1/z(^n)

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16
Q

y axis reflection

A

-1 0

0 1

17
Q

x axis reflection

A

1 0

0 -1

18
Q

y = x reflection

A

0 1

1 0

19
Q

y = -x reflection

A

0 -1

-1 0

20
Q

2 d rotation

A

cosx -sinx

sinx cosx

21
Q

3 x3

x = 0 reflection

A

-1 0 0
0 1 0
0 0 1

22
Q

y = 0 reflection 3x3

A

1 0 0
0 -1 0
0 0 1

23
Q

reflection z = 0

A

1 0 0
0 1 0
0 0 -1

24
Q

rotation about x axis

A

1 0 0
0 cosx -sinx
0 sinx cosx

25
Q

roation about y axis

A

cosx 0 -sinx
0 1 0
sinx 0 cosx

26
Q

z axis rotation

A

cosx -sinx 0
sinx cosx 0
0 0 1

27
Q

What is scalar product

A

a.b = /a//b/ . cosx

28
Q

what is scalar product if two lines are parallel

A

a.b = 0

29
Q

angle between 2 lines

A

cos x = /a.b/ divided by /a//b/

30
Q

angle between line and a plane

A

sin x = b.n divided by /b//n/

31
Q

angle between 2 planes

A

modulus of n.n divided by /n//n/

32
Q

how to find intersection of plane and line

A
  1. write equation of line as one single vector
  2. subsistutute vector into r.n = d form of plane equation
  3. solve to find lamda and then substitute lamda into line equation to get coordinates
33
Q

how to find intersection of two planes along a line

A

write cartesian from of each equation

eliminate one variable using simultaneous equations and express one variable in terms of the other

substitute the new equation back into original plane equation to get an equation in terms of the original eliminated variable

rewrite the equation found in step 2 and change the subject

then write form of line in cartesian form

34
Q

perpendicular distance between point and a line

A

find equation for line

find equation from a to b ( a being the point and b being a general point on the line)

AB is perpendicular to line so AB . direction of line = 0
thatll give you lamda

then sub lamda into AB equation and modulus of it is distance

35
Q

distance between point and plane

A

use formula bok

36
Q

distance between two parralell lines

A

find BA by doing line 1 - line 2

then set t=lamda - mu

BA is perpendicular to line 1

find t then sub back in and find modulus