Measurement of Physical Quantities: Fundamental and Derived Flashcards
(132 cards)
Equipment and Materials Needed for Measurement of Physical Quantities
Meterstick
Vernier Caliper
Micrometer
Stopwatch
Cylindrical Hollow Metal Block
Spherical Metal Block
Dynamic Cart
Dynamic Track
Physics helps us understand the physical universe by measuring fundamental quantities such as
distance
length
time
can measure internal dimensions using the uppermost jaws, external
dimensions using the lower jaws
vernier calipers
Vernier calipers commonly used in industry provide a precision to a hundredth of a millimeter or ho wmany micrometers
10 micrometers
is a device used widely in mechanical engineering and machining as well
as most mechanical trades for precision measurement.
micrometer
The spindle of an ordinary metric
micrometer has _ threads per millimeter, and thus one complete revolution moves the
spindle through a distance of 0.5 millimeter.
2 threads
. Thus, the reading is given by the number of ___ divisions
visible on the scale of the sleeve plus the particular division on the thimble which coincides
with the axial line on the sleeve.
milimmeter
what is measured for the length
laboratory table (using meter stick)
cylindrical hollow metal block (using Vernier Caliper)
spherical metal block (using Micrometer caliper)
what mass is measured
cylindrical hollow metal block
sphere
what is measured for a dynamic cart to travel a distance of 2m
time
derived quantities measured after experiment
area of table
volume/density of cylindrical hollow metal block and metal sphere
densities by percentage error
speed of dynamic cart
measure the area of the table if
length = 4.01 m
width = 1.01m
area = 4.05m^2
measure the radius if diameter is 1.245 cm
0.6225cm
1m is equals to __ cm
100
1m is equals to __ mm
1000
1m is equals to ___ um
1000000
1m is equals to __ km
0.001km
formula for volume of hollow cylindrical metal block
V = π (R2 -r2)h
where R = outer diameter
r - lower diameter
density formula
density = mass/volume
true value of aluminum
2.71x10^3 kg/m^3
calculate the volume given
Do = 1.245cm
Di = 0.66cm
H = 8.805cm
M = 21.0g
7.71 cc
calculate the density given
m = 21.0g
v = 7.71cc
2.72g/cc
calculate percentage error given
actual density = 2.78g/cc
theoretical density = 2.71/gcc
2.58%
percentage error formula
measured - actual /actual * 100