Set
a well-defined collection of elements
The Natural Integers
N = (1, 2, 3…..)
Q
Set of all rational numbers
Q^c
set of all irrational numbers
the “c” E
belongs to
backwards E
there exists
upside down A
for every
: or I
such that
->
an implication, f=A->B
Closure
x + y E R x . y E R
Commutative rules
x + y = y + x x . y = y. x
associative rules
(x+y) +z = x + (y+z) (xy) z = x (yz)
identity elements
x + 0 = x x . 1 = x
inverse rules
x + (-x) = 0 x . 1/x = 1
distributive rule
axiom connecting addition and multiplication
x(y+z)=xy+xz
i^0
1
i^1
i
i^2
-1
i^3
-i
i^4
1
i^5
i
i^6
-1