Flashcards in Genetics and Molecular Biology Deck (36):
man and woman are both affected by an autosomal dominant disorder with 80% penetrance in all affected individuals. They are both heterozygotes for the disease causing mutation. which of the following is the probability that they will produce a phenotypically normal offspring?
probability that a child receives the dominant trait multiplied by the penetrance of the trait=risk of the child expressing the abnormal phenotype.
expression of normal phenotype=probability of receiving dominant trait-number from 1st calculation:
75% chance of receiving disease causing gene (RR and 2Rr)
0.75 X 0.80=0.6 or 60%
also 25% will be geneotypically normal (rr)
So, probability of phenotypically normal child= 25%+15%=40%
for a autosomal recessive condition, if a phenotypically normal child is born to parents that are both heterozygous for the condition, the probability that the child is heterozygous for the condition is
2/3. (Rr, Rr, and RR)
not 1/2 b/c we already know that the child is not (rr) so it's not included in the overall probability calculation.
Fragile X syndrome- inhereitance, gene effected presentation, male vs female
-trinucleotide repeat (CGG)
-affects methylation of FMR1 gene
-macro-orchidism, long face with large jaw, large everted ears, autism, mitral valve prolaspe
-more severe in males b/c they only have 1 X chromosome
-think Xtra large-testes, jaw, and ears
molecule for responsible for adding RNA primer to initiate DNA eukaryotic replication, not polymerase III because
-polymerase III is found in prokaryotics only
-primase is a complex of proteins that synthesize a short fragment of RNA. required before DNA can be synthesized
capping vs splicing vs polyadenylation at 3' end of growing RNA transcript
capping- occurs immediately after synthesis of first 30 nucleotides. triphosphate of GTP condenses with 5'diphosphate to make a cap that is recongnized during protein synthesis and protects RNA
splicing-splice acceptor site on RNA at 3' end is AG (note it's GU on 5'end) these high conserved sequences are needed for correct spicing of introns and exons.
polyadenylation-occurs near the 3' end. an AAUAAA sequence is recognized cleaved and then poly-A polyerase add hundreds of adenylate residues
findings in osteogenesis imperfecta are best explained due to what (genetic term) and not multiple mutation because?
osteogenesis imperfecta is an example of a disease in which a single mutation leads to multplie features (pleiotrophy).
it is cause by single mutation
allelic heterogeneity vs locus heterogeneity vs pleiotrophy
-different mutations in single locus alleles leads to one feature (albinism)
-different mutations in different locus leads to one feature (b-thalasemmia)
-a single mutation leads to multiple features (osetogenesis imperfecta)
-to determine which restriction fragments of DNA are associated with a particular gene, genetic relatedness, indirect mutation analysis within families
-to measure sizes and amts of mRNA to determine gene expression
-measure amt of antigen or proteins, determine translation
-detect and characterize DNA-bind proteins and where on DNA they bind
-detect specific DNA,RNA, protein or antibody
all above techniques need electrophoresis except Dot (Slot)
which biochemical techniques can be used to fine disease causing alleles?
PCR- amplify DNA sequences
or Dot (slot)- use probes to find disease causing DNA, RNA, protein, or antibody
disease associated with DNA repair defect
-direct pyrimidine dimer repair
-global genomic nucleotide excision repair (GGNR)
-transcription-coupled nucleotide repair
-non-homologous end joining
-none (mediated by photolyase)
-xeroderma pigmentosum* (loss of ability to remove UV-radiation-induces pyrimidine dimers)-can lead to disease although photolyase can't
-developmental defects (loss of ability to repair sequences removed by GGNR
-HNPCC or Lynch syndrome*
mutation in hMSH2 of hMLH1 leads to
defective mismatch repair- Lynch syndrome HNPCC
- vs sporadic rentiblastoma
-how PCR is used to detect between sporadic and heritable forms of a disease? i.e retinoblastoma
-many tumors in both eyes, body, and autosomal dominant inheritance
-one tumor in one eye, no increased risk of other tumors compared to general population, not passed to offspring
-sporadic-cells other than tumor will show normal two alleles
-heritable- 1 chormosome will show deletion or mutation in all cells of body. tumor will have 2 mutations
def of Biochem technique called DNA footprinting
tech used to detect DNA binding proteins by comparing the fragmentation patterns (after digestion with DNase I) of DNA bound to proteins and DNA not bound to protein. Assume binding protein protects DNA sequences from being digested with DNase I
Fluorescence-activated cell sorting (FACS)- definition, purpose
-antibodies coupled to fluorescent markers to detemrine surface markers on whole cells
-can determine stage of maturity or activation of cells (i.e. WBCs)
how to solve this problem the using gametes instead of mating calculations:
autosomal recessive disease has a general population frequency of 1%. a heterozygous mans marries a woman from the general population. what is the probability that he and his partner will have an child affected with the disorder.
for the man there's a 50% chance (since he's a know heterozygous) that one of his sperm carrying the defective allele will fertilize the egg
for the woman her chance (since she's from the general population) of her eggs carrying the defective allele is equal to the allele frequency q=0.10.
chance of child effected will disease is 0.5 X 0.1= 0.05
two day year old baby develops tetany and has dsymorphic facies, with low-set ears and micrognathia, and decreased serum Ca2+ levels. child has what? not patau's because?
-DiGeorge Syndrome* (22q11), absence of thymus and parathyroid leads (improper development of 3rd and 4th pharyngeal pouches) to manifestations
-Patau's presents with intellectual disability, physical abnormalities (heart defect, hypotonia, micropthalmia, cleft lip and palate, and extra digits and toes)*
genetic inheritance of Marfan's
first occurrence of autosomal dominant condition in a family is usually caused by
new mutation that occurred in one of the gametes transmitted by one parent
a defect in enzyme that has a normal mRNA expression is due to nonsense mutation and not RNA splicing because
nonsense mutation can lead to truncated product that can be abnormal in shape leading to decreased function or rapid degradation
-RNA-splicing defect would affect mRNA expression levels and size
if there is male to male transmission of the disease then what do you know about the inheritance of a disease? what don't you know? how do you determine the what you don't know?
-know that is autosoma*
-don't know recessive vs dominant
-dominant will be seen in multiple generations* (50% chance) unless incomplete penetrance
recessive will skip generations (25% chance)*
Barr body are seen in individuals with what genotype?
must have at least two or more X chromosomes.
i.e. normal females and Klinefelter (47,XXY)
trinucleotide expansion in Huntington's leads to loss of function or gain of function mutation?
thought to produce a toxic gain of function
for an autosomal recessive disease what is the carrier frequency approximately equal to?
or approximately 2q (because value of p is close to 1 b/c q is so small) p+q=1
-name of technique used to determine when and in which parent gamete non-disjunction occurs?
-result if occurs in meiosis I
-result if occurs in meiosis II
-result if nondisjunction occurs during 1st mitotic division
-restriction fragment length polymorphism
-child receives two DIFFERENT alleles from parent
-child receives two SAME alleles (failed splitting of sister chromatids) from parent
-mosaic genotype (some cells have one genotype while other cells have another)
reason for difference in severity of Becker's and Duchenne muscular dsytrophy
in-frame deletion or insertions in the becker form and frameshift deletions or insertions in the Duchenne form
Robertsonian translocation-def and name two types, which one leads to disease? give 2 examples
chromosomal translocation. (usually 13,14,15,21,22)
non-reciprocal-two large arms join and two small arms are lost- associated with Down's and Patau's
reciprocal-DNA is exchanged- usually no abnormal phenotype
presentation of Klinefelter syndrome
-most common congenital abnormality causing primary hypogonadism
-most common genotype is 47,XXY resulting form nondisjunction of sex chromosomes
-abnormal male secondary characteristics (small testes, small penis, and gynecomastia) and mental retardation
how do you use monozygotic twin concordance and dizygotic twin concordance to determine inheritance of a trait, (autosomal recessive, dominant, or multifactorial)
-if DZ is less than 50% of MZ then can't be solely autosomal dominant
-if DZ is less than 25% of MZ then can't be solely recessive
-so must be multifactorial (some genetic and environmental component)
with a multifactorial inheritance what is risk of infecting 2nd sibling if 1st sibling has disease compared to
-monozygotic concordance rate
-approximately equal to
-higher risk than population (b/c there's some genetic effect)
-lower risk than MZ (b/c there's some environmental effect)
approximately equal to DZ or square root of general population risk
trisomy vs triploidy
-extra copy of a single chromosome (i.e. Down's trisomy 21)
-3 extra copies of all chromosomes
cross like structure produced when a homologous pair of chromosomes aligns to exchange genetic material
formal name for pairing of homologous chromosomes with which meiosis begins
reasons for muscular dystrophy in males females?
males-recombination event that gives rise of a frameshift mutation
females-new mutation (unequal crossing over in females at meiosis I)
given phenotypically normal parents what is the probability that a female sibling of a male affected by an X-linked recessive disease will give birth to an affected child
p1-sister is carrier=1/2 (mother not father is carrier b/c neither parent has disease
p2- sister (if carrier) will pass disease to offspring. =1/2 (only passes on 1 of 2 X chromosomes)
p3-offspring of sister is male (only male will have disease). =1/2 (50% chance she will have a male)
given carrier frequencies of an autosomal recessive disease what is probability that parents will give birth to child with disease?
must calculate probability will be a carrier (carrier frequency) and multiply by chance that EACH parent will pass along mutated gene (1/2).
So, (carrier frequency 1of 1st parent x 1/2) X (carrier frequency of 2nd parent x 1/2)= carrier frequency X carrier frequency X 1/4