Immunohematology Final Lab Practical (Labs 7-14) Flashcards

1
Q

At which phase of testing do most clinically significant allo-antibodies react? (2)

A

37C (Incubation) & AHG

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2
Q

Why is it important to match the lot number of panel cells used in the antigram?

A

To appropriately identify the patient’s antibody. Each antigram has a different antigen expression on the cells. Using the wrong antigram could identify the wrong antibody.

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3
Q

If polyspecific AHG is used for a panel, what would cause an IgM to react?

A

Complement (C3)

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4
Q

Which antibody is most likely?

A

C

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5
Q

Which antibody(ies) cannot be ruled out?

A

Kell

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6
Q

Why is cell #3 weaker than the others?

A

Dosage - heterozygous for C/c

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7
Q

Which of the following additional cells need to be run?:
a. C=, K+ cell
b. C+, K+ cell
c. C=, K+ cell
d. C+, K= cell

A

a. C=, K+ cell

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8
Q

Which antibody or antibodies cannot be ruled out or half-crossed? (7)

A

-C
-e
-S
-P1
-Lewis a
-K
-Fy b

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9
Q

Does the reactivity fit any single antibody?

A

Yes, little e.

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10
Q

How would you eliminate the antibodies not crossed off? (select all that apply):
a. Phenotype the patient
b. Run select cells
c. Neutralization
d. DTT

A

a. Phenotype the patient
b. Run select cells

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11
Q

If a patient’s antibody screen is positive, how can the identity of the antibody be determined?:
a. Perform a panel
b. Perform an elution
c. Perform a weak D test
d. Request a redraw

A

a. Perform a panel

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12
Q

All of the following will result in a false negative IAT except:
a. Failure to add patient plasma
b. undercentrifugation
c. Correctly following the IAT procedure, adding patient plasma, commercial screening cells, and AHG
d. Failure to add AHG

A

c. Correctly following the IAT procedure, adding patient plasma, commercial screening cells, and AHG

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13
Q

Failure to add patient plasma, undercentrifugation, and failure to add AHG will cause what type of result for IAT testing?

A

False negative

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14
Q

The following is used to denote what type of reaction on a data sheet?

A

Microscopic positive

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15
Q

Determine the patient’s ABO given the following reactions:

A

A2B positive

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16
Q

Determine the patient’s ABO given the following reactions:

A

A2 with anti-A1, Rh invalid due to positive reacting weak D control

17
Q

Determine the patient’s ABO given the following reactions:

A

A1 positive

18
Q

Based on the following IAT results, what type of antibody is most likely present?
(warm/cold, auto/allo, IgG/IgM)

A

Warm auto antibody

19
Q

Based on the following IAT results, what type of antibody is most likely present?
(warm/cold, auto/allo, IgG/IgM)

A

Cold auto antibody

20
Q

Based on the following IAT results, what type of antibody is most likely present? (single/multiple, auto/allo, IgG/IgM, warm/cold)

A

Multiple IgG antibodies

21
Q

Based on the following IAT results, what type of antibody is most likely present? (single/multiple, auto/allo, IgG/IgM, warm/cold)

A

Single allo IgG antibody

22
Q

Interpret the reaction:

A

B with anti-I

23
Q

Interpret the reaction:

A

A2 with anti-A1

24
Q

Interpret the reaction:

A

A1 with anti-H

25
Q

Interpret the reaction:

A

A2B

26
Q

Interpret the reaction:

A

B with cold alloantibody

27
Q

Interpret the reaction:

A

O with anti-i

28
Q

Interpret the reaction:

A

A1 with anti-IH

29
Q
A

A1 with anti-I

30
Q
A

AB with anti-i

31
Q
A

O with alloantibody

32
Q

Which antibody is most likely?

A

Lewis A

33
Q

From the panel, which antibody(s) cannot be ruled out?

A

All are ruled out

34
Q

What additional method could be used to confirm antibody identification?

A

Neutralization

35
Q

What is the most likely phenotype of Jane Doe?

A

LeA=, LeB=
(have to be negative for both to create an antibody)

36
Q

Which antibody(s) is most likely present?

A

Kell

37
Q

What percent of the white population would be compatible with this antibody?
a. 2%
b. 9%
c. 98%
d. 91%

A

d. 91%

38
Q

What percent of the white population would be compatible with this antibody and be the same ABO/Rh type?
a. 44%
b. 35%
c. 6%
d. 68%

A

b. 35%
-Type O: 45%
-