17.b Probability Extended

Question 1

Solve:

Answer 1

Question 2

Solve using the combination method

Answer 2

Question 3

Solve using the combination method

Answer 3

Question 4

Solve:

Answer 4

Question 5

Solve:

Answer 5

Question 6

Solve:

Answer 6

Question 7

How would you solve this?

Answer 7

USING ALGEBRAIC EQUATIONS

Question 8

If the probability of removing a blue candy from a jar of candies is 1/4, what can you conclude?

Answer 8

You can conclude that there are x occurrences of blue candy for every 4x occurrences of candies in the jar: 1x / 4x

So this could be 10 blue candies / 40 total candies

Do NOT assume that 1/4 means that there is 1 blue candy for 4 total candies, that is incorrect!

Question 9

Knowing the probability of choosing certain items from a group is not sufficient information for determining ____________________________

Answer 9

Knowing the probability of choosing certain items from a group is not sufficient information for determining HOW MANY ITEMS ARE IN THE GROUP

Question 10

How would you solve this?

Answer 10

Question 11

Solve:

Answer 11

Question 12

Imagine you create a seven-letter code (from any letters of the alphabet), what is the probability you would choose “VPNTXDW”?

Answer 12

VPNTXDW is just 1 code
there are 26^7 possible codes, so…

1 / 26^7

Question 13

Imagine you create a seven-letter code (from any letters of the alphabet), what is the probability you would choose either “VPNTXDW” or “JKLMFGW”?

Answer 13

Either are just 1 code, one possibility,
there are 26^7 possible codes, so…

1 / 26^7 + 1 / 26^7 = 2 / 26^7

Question 14

Solve:

Answer 14

Question 15

Solve:

Answer 15

Question 16

If A and B make up two sets in a probability question, then… (equation):

Answer 16

Question 17

If A and B are two non-mutually exclusive events, then… (equation):

Answer 17