CR Prob And Stats - Trimester 1 Final Flashcards Preview

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Flashcards in CR Prob And Stats - Trimester 1 Final Deck (18)
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Bar graphs (5)

Represent each category as a bar

Easier to make and read than pie charts

Often better to order bars in order of height (helps see what occurs most)

Compares any set of quantities that are measured in the same units

Represents multiple categories

1

Interpreting graphs (4)

Shape (skewed, symmetrical)
Outlier (1.5 x IQR)
Center
Spread (range)

2

Skewed to the left (2)

➡️↗️↘️

Mean is to left of median

3

Skewed to the right (2)

↗️↘️➡️

Mean is to the right of median

4

stemplots and Histograms (3)

Histograms and stemplots graph the distribution of a quantitative variable

Histograms shows shape of distribution and represents ONE quantitative variable

Stemplots present exact

5

Density curve

Has a total area of 1

6

Mean (2)

μ

Balance point of curve

7

For symmetric curves...

Mean and median are equal

8

Normal curve (5)

N(μ, σ)

Has normal curve N(0,1)

All normal curves have the same overall shape: symmetric, single-peaked, bell shaped

2nd--> distr --> normalcdf(low, high, mean, std dev) ((find percentiles, proportion))

2nd --> distr --> invnorm(area, mean, std dev) ((find score))

9

How do you find the z score? (2)

Z = x - μ / σ


X = random point

10

68-95-99.7 rule (3)

68%- μ±σ

95%- μ±2σ

99.7%- μ±3σ

11

Resistant measures (3)

Median

Quartiles

Mean and standard deviation are not resistant

12

Measure of spread (4)

Std deviation - if I used mean

IQR - if I used median

Range - (max-min) very sensitive to outliers

Variance

13

How to determine if a number is an outlier? (3)

1.5 x IQR = #

Q1 - # = anything below is outlier

Q3 + # = anything above is outlier

14

Measures of center (2)

Mean - use if symmetrical
Median - use if data is skewed w/ outliers

15

Standard deviation (4)

S = 0 --> no spread

S>0 --> S gets larger

S = always > or = 0

Not resistant to outliers

16

P(A and B) =

P(A and B) = P(A) x P(B|A)

17

Binomial probability (6)

nCr = (p^k)(q^n-k)

N = # of trials
K = # of successes
n-k = # of failures
P= probability of success in one trial
Q = 1-P = probability failure in one trial