Pumping Apparatus Flashcards
Friction Loss Coefficient - Single Hoselines:
Hose diameter of 1 3/4 inch with 1 1/2 inch couplings has a “coefficient” fiction loss of:
15.5
The friction loss in 100 feet of 2 1/2 inch hose flowing 200 GPM is 10 PSI. What would the friction loss in 300 feet of 2 1/2 inch hose flowing 200 GPM be?
30 PSI
Friction Loss Coefficient - Single Hoselines:
Hose diameter of 2 1/2 inches has a “coefficient” friction loss of:
2
Friction Loss Coefficients - Siamesed Lines of Equal Length:
Two 2 1/2 inch hoses has a “coefficient” fiction loss of:
0.5
Friction Loss Coefficients - Siamesed Lines of Equal Length:
Two 3 inch hoses with 2 1/2 inch couplings has a “coefficient” fiction loss of:
0.2
What is the formula to find friction loss? Equation A:
Friction loss = ( )( )sq( )
Friction Loss = (coefficient #) x
flow-rate in hundreds of GPM / 100)sq x (hose length in hundreds of feet / 100
Formula to find “elevation pressure” is:
- When # of feet is given:
- When # of stories/floors are given:
EP = (0.5)(Height in feet)
Or
EP = (5psi)(# of stories - 1)
An engine is pumping through 500 feet of 2 1/2 inch hose flowing at 300 gallons per minute and the nozzle is operating 100 feet below the pump. Friction loss combined with elevation loss would be:
40psi
FL=(coefficient)(flow rate / 100)sq(hose length /100) FL=(2)(300 / 100)sq(500 / 100) FL=(2)(3)sq(5) FL=(2)(9)(5) FL=90 ----------------------------------------- EP=(0.5)(100) EP=50 ----------------------------------------- TFL = FL-EP TFL = 90-50 TFL = 40psi
Water exerts a pressure of 0.434 PSI per foot of elevation.
- When a nozzle is operating at an elevation higher than the apparatus, this pressure is exerted back against the pump. To compensate for this pressure “loss”, elevation pressure must be _____ to the friction loss to determine total pressure loss.
- Operating a nozzle lower than the pump results in pressure pushing against the nozzle. This “gain” in pressure is compensated for by _____ the elevation pressure from the total friction loss.
- adding
2. subtracting
An engine is pumping through 150 feet of 2 1/2 inch at 300 GPM and has a nozzle pressure of 50 psi.
- The friction loss of the hose would be: (exam sts: “FL would be most nearly:”)
- The friction loss of the hose and nozzle would be:
1. FL=(2)(300/1)sq(150/1) FL=(2)(3)sq(1.5) FL=(2)(9)(1.5) FL= 27 psi (^ exam answer, didn't add NP?)
- TFL= FL+NP
TFL= 27+50
TFL= 77 psi
- When solid stream nozzles are used on hand lines, they should be operated at _____ PSI nozzle pressure.
- A solid stream master stream device should be operated at _____ PSI.
- 50 PSI
2. 80 PSI
In most cases, (1)_____ PSI is used as a nozzle pressure for solid stream hand lines equipped with up to 1 1/2 inch nozzles. If greater rate and volume are needed, the nozzle pressure may be raised to (2)_____ PSI without becoming unmanageable. Above this point, solid streams become increasingly difficult to handle.
- 50 PSI
2. 65 PSI
The most amount of water that can be safely flowed through a handline is:
A. 250 GPM.
B. 300 GPM.
C. 350 GPM.
D. 400 GPM.
C. 350 GPM
The friction loss in 600 feet of 2 1/2 inch hose flowing at 200 GPM is most nearly:
FL = (2)(200/100)sq(600/100) FL = (2)(2)sq(6) FL = (2)(4)(6) FL = 48 psi
The master stream is the “big gun” of the fire department:
- Smoothbore master streams are usually operated at _____ PSI
- and fog master streams at _____ psi.
- Master stream flows are usually _____ GPM or greater.
- 80 PSI
- 100 PSI
- 350 GPM
A hoseline is operating on the 10th floor of a high-rise building. The building is equipped with a standpipe system. What is the total pressure loss due to elevation at the base of the standpipe system?
EP = 5 PSI x (# of stories - 1) EP = 5 PSI (10 - 1) EP = 5 PSI (9) EP = 45 PSI
A hoseline is operating on the 12th floor of a high-rise building. The building is equipped with a standpipe system. What is the total pressure loss due to elevation at the base of the standpipe system?
EP = 5 PSI (# of stories - 1) EP = 5 PSI (12 - 1) EP = 5 PSI (11) EP = 55 PSI
Your pumper is operating from a hydrant. The static pressure is 90 psi, and the residual pressure is 82 PSI. You are supplying a hoseline flowing 300 GPM. Using the percentage method of calculating additional water available, what is the percentage drop in this layout?
Percent Drop = (Static-Residual)(100) / Static PD = (90-82)(100) / 90 PD = (8)(100) /90 PD = 800/90 PD = ~ 9%
Static/Residual Additional Hydrant Water:
If the percentage drop is 10% or less, _____ additional lines with the same flow as the line being used maybe added.
3
Static/Residual Additional Hydrant Water:
If the percentage drop is 11%-15%, _____ additional lines with the same flow as the original line may be added.
2
Static/Residual Additional Hydrant Water:
If the percentage drop is 16%-25%, _____ additional line equal to the flow of the original line may be added.
1
Static/Residual Additional Hydrant Water:
If the percentage drop is over 25%, _____ additional lines with the same flow as the original line may be added.
Zero
-More water may be available, but not as much that is flowing through the original line being used.
Your pumper is operating from a hydrant. The static pressure is 90 PSI, and the residual pressure is 82 PSI. You are supplying a hoseline flowing 300 GPM. Using the percentage method of calculating additional water available, how many more lines are available from this layout?
3 more lines
An automatic nozzle will maintain a constant nozzle pressure of _____ PSI, no matter how much the pump discharge pressure is above this figure. As pump discharge pressure is increased, the nozzle automatically enlarges its effective opening size (within the range of the nozzle) to match the flow.
100 PSI