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GFR and Renal clearance Flashcards

(19 cards)

1
Q

What is the meaning of freely filtered?

A

When something is filtered and as a result the concentration of it in plasma and filtrate is the same

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2
Q

What is the conditions when GFR equals renal clearance of a substance? What is the name of this ideal molecule

A

Freely filtered but either reabsorbed nor secreted

inulin

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3
Q

What is the formulae for renal clearance

A

(Concentration of substance in urine X volume of urine per minute)/ conc of substance in plasma

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4
Q

What properties of inulin make it an ideal molecule for getting an accurate GFR

A

Freely filtered

Not rebsorbed

Not secreted

not toxic

Measurable in urine and plasma

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5
Q

What happens if the renal clearance of substance is higher or lower than that on inulin

A

Lower- NET reabsorption; like Na in which 99% is reabsorbed

Higher - Net secretion

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6
Q

What substance can be used for measuring renal plasma flow ? Explain why

A

PAH- para-amino hippuric acid

PAH is secreted into tubules; hence all PAH arriving at arterioles should be in tubules and none leaves in renal vein. Provided PAH plasma conc isn’t too high

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7
Q

How do you calculate the rate at which PAH enters kidney per minute

A

[Plasma PAH] x RPF (Renal plasma flow rate)

N.B RPF is equal to it’s renal clearance

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8
Q

How do you calculate the rate at which PAH is excreted in urine

A

[Urine PAH] X Volume of urine excreted per minute

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9
Q

How do you calculate what proportion of blood entering glomeruli is filtered (filtration fraction)

A

Inulin clearance / PAH clearance

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10
Q

Why is PAH clearance rarely performed clinically when renal disease is suspected?

A

GFR measurement is sufficient to diagnose renal disease, hence no need to calculated filtration fraction (using PAH). Also PAH will need to be infused which will inconvenience the patient..

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11
Q

What are the problems what using inulin for estimating GFR

A

Not given orally as enzymes may break it down an hence lose it’s special properties

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12
Q

What are the 3 main methods for estimating GFR

A

Inulin clearance

Creaitnine clearance

57Cr EDTA clearance

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13
Q

What are the features for creaitnine clearance?

A

It’s endogenous

requires:

  • 24 hr urine collection
  • a single plasma sample taken at some time during clearance period

Bladder catheterisation is unnecessary as % volume error incurred by incomplete bladder emptying at the start and end of 24h urine collection is insignificant

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14
Q

What is the problem of using creatinine for GFR? How can it be resolved?

A

Some (tiny amount) is secreted into proximal tubule; hence GFR may be an overestimate

however there’s error in the colorimetric calculation in plasma creaitnine concentration; it measures the concentration of non-creatinine chromogens

Hence the 2 cancel out

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15
Q

Explain the shape of this curve

A

Some EDTA injected enters ECF (then try to equilibrate), some enter urinary system. Hence initially, theres a large decrease in EDTA activity in plasma. Amount leaving blood is equal to amount entering urinary system + amount entering ECF - amount entering blood via ECF

over time after equilibrium has been reached between blood and ECF, theres a steady decrease . Only EDTA leaving blood is though urinary system

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16
Q

Is there any need to collect urine using EDTA

A

No; as EDTA emits gamma radiation and hence can be measured

17
Q

How will the graph of EDTA acitve against time change of theres a renal disease

A

Renal disease means that there’s a lower rate of EDTA leaving the blood via the urinary system . The rate of decline will be shallower

18
Q

How can clearance be calculated from the EDTA activity vs time graph

what are the advantages of using EDTA

A

A second log graph is plotted and then slope calculated. The great the gradient, the higher the clearance.

Advantages are:

  • No need to collect urine samples
  • Injections of a single dose of EDTA
  • colleciton of 2-3 plasma samples - to map out straight line of the graph.
19
Q

How does the concentration of inulin in efferent arteriole and renal vein compare

explain why

A

Efferent arteriole inulin concentration is same as afferent arteriole

renal vein is lower due to reabsorption of water (99.9%)