Nakamura Human Physiology Lecture 8 Flashcards

(51 cards)

1
Q

Respiration

A
.Ventilation: Physically moving volumes of air
•Gas exchange
     –between air and blood in the lungs
    –between blood and tissues
•02 consumption
    –Cellular respiration
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2
Q

Conducting zone

A

-not for gas exchange
Anatomical structures air passes through before reaching the respiratory zone including:
–Mouth, nose, pharynx, larynx, trachea, primary bronchi, and bronchioles
-ends in terminal bronchioles
•Functions:
–Warms and humidifies inspired air
–Filters and cleans: Mucus traps airborne particles

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3
Q

Respiratory zone

A

.Region of gas exchange between air and blood
•Includes respiratory bronchioles and alveoli and alveolar sacs
-starts with respiratory bronchioles and ends in alveolus
•What is important for gas exchange?
–Moist environment
–Large surface area (60 – 80 m2) for diffusion

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4
Q

Properties of lung tissue

A

.Compliant (stretchable)
•Elastic
–Return to initial size after stretch
–High content of elastin proteins
•Elastic tension increases during inspiration and is reduced by recoil during expiration

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5
Q

Pleurae cavities

A

-thoracic cavity contains heart and lungs
-pleural cavity within thoracic, just lungs
-left and right pleural cavities sealed, air cannot pass through from one to the other
-Parietal pleura lines the inside of the thoracic wall
•Visceral pleura lines the surface of the lungs
•Pleural cavity is a fluid layer between the two coverings
•Visceral and parietal pleura stick together such that the lungs are suspended from the thoracic wall

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6
Q

Pressures

A

.Atmospheric pressure at sea level is 760 mMHg (micromercury)
-go deeper, higher pressure
-go higher, lower pressure
•Intrapulmonary (intra-alveolar) pressure
–Pressure in the alveoli
-higher than intrapleural
•Intrapleural pressure
–Constant pressure in the space between the pleurae
-is negative relative to the intrapulmonary pressure
•Transpulmonary pressure
-difference between the intrapulmonary and intrapleural pressures
–Slightly positive to keep the lungs pressed against the chest wall

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7
Q

Abnormal pressures

A

.Separation of the pleural membranes makes the intrapleural pressure less negative such that it equals the atmospheric pressure.
•If the intrapleural pressure equals the intrapulmonary pressure, the lung cannot expand.
•This condition is called a pneumothorax

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8
Q

Boyle’s law

A

.Changes in lung volume cause changes in intrapulmonary pressure
–Pressure of a gas is inversely proportional to its volume.
•Increase in lung volume decreases intrapulmonary (alveolar) pressure
–Air enters the lungs
•Decrease in lung volume, raises intrapulmonary pressure above atmospheric pressure
–Air exits the lung

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9
Q

4 processes/ types of respiration

A

Unforced and forced inspiration

Unforced and forced expiration

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10
Q

Unforced and forced inspiration

A

.Unforced (-3 mmHg)
•Diaphragm (vertical)
•Ext. intercostals, parasternal intercostals (lateral)
–Forced (-20 mmHg)
•Scalenes, pectoralis minor, sternocleidomastoid
Pressures indicate intrapulmonary pressure below atmospheric pressure

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11
Q

Unforced and forced expiration

A

Unforced (+3 mmHg)
•Passive process by recoil of lung, diaphragm, and thoracic muscles
–Forced (+30 mmHg)
•Int. intercostals (lateral)
•Abdominal muscles (vertical)
Pressures indicate intrapulmonary pressure whether below or above atmospheric pressure

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12
Q

Surface tension

A

-Force that causes alveoli to resist expansion
•H20 molecules on the alveolar surfaces are attracted to other H20 molecules
-similar to how water btwn glass cause the glass to stick together, occurs in the lungs as well

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13
Q

Law of Laplace

A

•Pressure in alveoli is directly proportional to surface tension and inversely proportional to radius of alveoli

  • alveoli bigger, tension smaller
    - because surfaces are farther apart
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14
Q

Surfactant

A

-Phospholipid produced by alveolar type II cells
•Lowers alveolar surface tension by separating H20 molecules
•As alveoli radius decreases, surfactant’s ability to lower surface tension increases
•Respiratory Distress Syndrome (RDS)

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15
Q

Carbon dioxide

A

transported from the body cells back to the lungs as:

1 - bicarbonate (HCO3) - 60% formed when CO2 (released by
cells making ATP) combines with H2O (due to the enzyme
in red blood cells called carbonic anhydrase)
2 - carbaminohemoglobin - 30% formed when CO2 combines
with hemoglobin (hemoglobin molecules that have given up
their oxygen)
3 - dissolved in the plasma - 10%

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16
Q

Respiratory center

A

-medulla and pons
-Stimulated by chemoreceptors (sense how much CO2 in body)
-Inspiration: more active
-Apneustic center (located in the pons) - stimulate I neurons
-I neurons (inspiratory centre) located in the medulla
Expiration: more passive
-Pneumotaxic center (pons) - inhibits apneustic center & inhibits I neuron
-goes to e neuron (expiratory centre) in the medulla
-inhibits inspiration

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17
Q

Rhythmicity center of medulla

A

.The rhythmicity center of the medulla:

1) controls automatic breathing
2) consists of interacting neurons that fire either during inspiration (I neurons) or expiration (E neurons)
a) I neurons - stimulate neurons that innervate respiratory muscles (to bring about inspiration)
b) E neurons - inhibit I neurons (to ‘shut down’ the I neurons & bring about expiration

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18
Q

Factors involved by increasing respiratory rate

A

.Chemoreceptors: located in aorta & carotid arteries (peripheral chemoreceptors) & in the medulla (central chemoreceptors)
2. Chemoreceptors (stimulated more by increased CO2 levels than by decreased O2 levels) > stimulate Rhythmicity Area > Result = increased rate of respiration
Give patients 95 oxygen 5 co2 otherwise shut down respiratory center

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19
Q

Why there is not increased CO2 in the blood during heavy exercise

A

Possible factors:
a) reflexes originating from body movements (proprioceptors)
b) increase in body temperature
c) epinephrine release (during exercise)
d) impulses from the cerebral cortex (may simultaneously stimulate rhythmicity
area & motor neurons)

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20
Q

Inspiration

A

.Contraction of external intercostal muscles
-elevation of ribs & sternum
-increased front- to-back dimension of thoracic cavity
-lowers air pressure in lungs
-air moves into lungs
Contraction of diaphragm
-diaphragm moves downward
-increases vertical dimension of thoracic cavity
-lowers air pressure in lungs
-air moves into lungs

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21
Q

Expiration

A

To exhale:
relaxation of external intercostal muscles & diaphragm
-return of diaphragm, ribs, & sternum to resting position
-restores thoracic cavity to preinspiratory volume
-increases pressure in lungs
-air is exhaled

22
Q

FEV1

A
1 second forced expiratory volume test
-how much air forced out in 1 sec
Normal: expiratory: 3.2L/sec
               Residual volume: 1.8L 
5L-1.8L / 5L-1L * 100 = 80%
23
Q

Restrictive disorder

A
  • vital capacity is reduced (tidal volume, inspiratory reserve volume, and expiratory reserve volume)
  • FEV1 is normal
  • pulmonary fibrosis (lung damage), more fibers in lung, less elastin protein in fiber
24
Q

Obstructive disorder

A
  • vital capacity is normal
  • FEV1 is reduced
    - residual volume: 2.5L
    - expiratory: 2.5L/ sec
    - 5L-1.8L / 5L-1L * 100= 62.5%
  • asthma
25
Gas exchange and Daltons Law
.Total pressure of a gas mixture is equal to the sum of the pressures that each gas in the mixture exerts independently. •PATM = PN2 + P02 + PCO2 = 760 mm Hg P= partial pressure Milli Mercury
26
Inspired air
``` H20: variable CO2: 000.3 mMHg O2: 159 mMHg N2: 601 mMHg Total pressure: 760 mMHg Milli Mercury ```
27
Alveolar air
``` .H20: 47 mMHg CO2: 40 mMHg O2: 105 mMHg N2: 568 mMHg Total pressure: 760 mMHg ```
28
Significance of blood PO2 and PCO2 measurement
-At sea level, P02 of arterial blood is about 100 mMHg •P02 level in the systemic veins is about 40 mMHg •PC02 is 46 mMHg in the systemic veins
29
Hemoglobin and oxygen transport
-280 million hemoglobin molecules in each RBC •Each hemoglobin has 4 polypeptide chains (2 alpha and 2 beta) and 4 hemes •Each heme has 1 iron atom that can combine with 1 molecule O2.
30
Hemoglobin
.Oxyhemoglobin is hemoglobin with bound O2 •Deoxyhemoglobin is hemoglobin that does not have bound O2 Deoxyhemoglobin goes to lungs, binds to oxygen, and becomes oxyhemoglobin, in tissues oxygen unbinds (releases), becomes Deoxyhemoglobin
31
Oxyhemoglobin dissociation curve
S curve - sigmoidal-shaped curve -hemoglobin is almost (97%) saturated with O2 at a PO2 of 100mMHg -about 25% of the O2 is unloaded at the tissue @ partial pressure oxygen 40 how much hemoglobin saturated 75 and unsaturated 25 (veins at rest) @partial pressure oxygen 100 (arteries) how much hemoglobin saturated 100
32
Shifts in oxyhemoglobin dissociation curves
-Change in the position of the curve indicates a change in hemoglobin affinity for O2 and a change in the amount of O2 delivered to the tissues •These factors can cause such a shift: “Right shift”- releasing O2 (affinity decrease) •1) lower pH •2) increased temperature •3) more 2,3-diphosphoglycerate •4) increased levels of CO2 * 2,3-DPG is a side product of anaerobic glycolytic passway (less oxygen in body, increase anaerobic pathway so more DPG released) - 2,3-DPG affects oxygen binding affinity by binding in a small cavity at the center axis of deoxygenated hemoglobin. - When bound, 2,3-DPG stabilizes the deoxygenated conformation of hemoglobin, greatly diminishing the binding of oxygen and facilitating oxygen unloading to tissues
33
Muscle myoglobin
-Slow-twitch skeletal fibers and cardiac muscle cells are rich in myoglobin •Facilitates the transfer of 02 from blood to the mitochondria within muscle cells •It only releases the O2 when the PO2 is very low: when the Hb cannot supply O2 fast enough and the demand is great -myoglobin has 1 heme -myoglobin has a high affinity for oxygen. (muscle able to tolerate lower oxygen) -PO2 35, hemaglobin: 50%, myoglobin: 95% oxygen saturation -P50 hemoglobin is PO2 35 ish -P50 myoglobin PO2 very low close to zero
34
Acclimatization to high altitude
Physiological adjustment of an individual to a different climate •Changes in ventilation –Hypoxic ventilatory response produces hyperventilation and an increase in tidal volume •Affinity of hemoglobin for O2 –Low oxyhemoglobin content stimulates production of 2,3-DPG, which decreases affinity of hemoglobin for O2 (releases oxygen) •Increased O2 carrying capacity of blood –Kidneys secrete erythropoietin, which stimulates the production of RBCs and hemoglobin
35
How much oxygen in the blood?
.plasma: no cells, .3 mL oxygen | Whole blood: with cells. 20ml oxygen. needs more oxygen in blood to match plasma cuz cells take oxygen
36
Sea level
Atm pressure: 760 PO2 (air): 159 PO2 (alveoli): 105 PO2 (arterial blood): 100
37
2000 feet above sea level
Atm pressure: 707 PO2 (air): 148 PO2 (alveoli): 97 PO2 (arterial blood): 92
38
4000 feet above sea level
Atm pressure: 656 PO2 (air): 137 PO2 (alveoli): 90 PO2 (arterial blood): 85
39
8000 feet above sea level
.Atm pressure: 564 PO2 (air): 118 PO2 (alveoli): 79 PO2 (arterial blood): 74
40
20000 feet above sea level
Atm pressure: 349 PO2 (air): 73 PO2 (alveoli): 40 PO2 (arterial blood): 35
41
30000 feet above sea level
Atm pressure: 226 PO2 (air): 47 PO2 (alveoli): 21 PO2 (arterial blood): 19
42
Numbers on s curve
Normal (ph 7.4) at 20 PO2: 32% saturation Right shift (ph 7.2) at 20 PO2: 22% Normal at 40 PO2: 75% Right shift: 62%
43
Lung volume
Four nonoverlapping components of the total lung capacity
44
Tidal volume
Unforced | The volume of gas inspired or expired unforced
45
Inspiratory reserve volume
Max volume of gas that can be inspired during forced breathing in addition to tidal volume
46
Expiratory reserve volume
Maximum volume of gas that can be expired during forced breathing in addition to tidal volume
47
Residual volume
The volume of gas remaining after a maximum expiration (dead space, unable to completely exhale so a bit left over)
48
Total lung capacity
Total amount of of gas in the lungs after a maximum inspiration Everything
49
Vital capacity
Maximum amount of gas that can be expired after a maximum inspiration Tidal volume + inspiratory reserve volume + expiratory reserve volume
50
Inspiratory capacity
Max amount of gas that can be impaired after a normal tidal expiration Tidal volume + inspiratory reserve volume
51
Functional residual capacity
Amount of gas remaining in the lungs after a normal tidal expiration Expiratory reserve volume + residual volume